# How much stronger is the gravitational pull of Saturn from the sun?

##### 1 Answer
Jan 29, 2016

${F}_{G r a v i t y} = 33.6653 \cdot {10}^{23} \frac{N {m}^{2}}{k {g}^{2}}$

#### Explanation:

We know:

${F}_{G r a v i t y} = G \frac{M m}{R} ^ 2$

Now, we have the value of $G$. Consider $M$ as mass of Sun. $R$ the distance between Saturn and Sun and $m$ mass of Saturn

So:

$G = 6.673 \cdot {10}^{-} 11 \frac{N {m}^{2}}{k {g}^{2}}$
$M = 1.989 \cdot {10}^{30} k g$
$m = 5.683 \cdot {10}^{26} k g$
$R = 1.433 \cdot {10}^{11} m$

${F}_{G r a v i t y} = 6.673 \cdot {10}^{-} 11 \frac{\left(1.989 \cdot {10}^{30} k g\right) \cdot \left(5.683 \cdot {10}^{26} k g\right)}{1.433 \cdot {10}^{11}} ^ 2$

$= 6.673 \cdot {10}^{-} 11 \frac{11.3035 \cdot {10}^{56}}{2.0535 \cdot {10}^{22}}$

$= 6.673 \cdot \frac{11.3035 \cdot {10}^{23}}{2.0535}$

$= 6.673 \cdot 5.045 \cdot {10}^{23}$

${F}_{G r a v i t y} = 33.6653 \cdot {10}^{23} \frac{N {m}^{2}}{k {g}^{2}}$

This is the force of gravity between Saturn and Sun.