How much work does it take to lift a 58 kg  weight 4 m ?

Mar 11, 2018

The work done here is negative with magnitude $= 2320 J$

Explanation:

Here the magnitude of work done is directly equal to the product of Weight and the displacement
WD $= 580 N \times 4 m$

$\therefore$WD $= 2320 J$

NOTE : For the sake of simplicity, I took 'g' = (10m )/s^2

Mar 12, 2018

I get $2274 \setminus \text{J}$ to the nearest whole number, assuming $g = 9.8 \setminus {\text{m/s}}^{2}$.

Explanation:

Well, the force here is the weight of the box.

Weight is given by $W = m g$.

We got: $m = 58 \setminus \text{kg}$, $\therefore W = 58 \cdot 9.8 = 568.4 \setminus \text{N}$

Work is given by the equation: $W = F \cdot d$

We got: $F = 568.4 \setminus \text{N",d=4 \ "m}$

$\therefore W = 568.4 \setminus \text{N"*4 \ "m"=2273.6 \ "J"~~2274 \ "J}$