How much work does it take to lift a #58 kg # weight #4 m #?

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Answer 1 · 2018-03-11T18:59:28

The work done here is negative with magnitude #=2320J#

Here the magnitude of work done is directly equal to the product of Weight and the displacement
WD #= 580N xx4m#

#:.#WD #=2320J#

NOTE : For the sake of simplicity, I took #'g' = (10m )/s^2#

Answer 2 · 2018-03-12T00:36:08

I get #2274 \ "J"# to the nearest whole number, assuming #g=9.8 \ "m/s"^2#.

Well, the force here is the weight of the box.

Weight is given by #W=mg#.

We got: #m=58 \ "kg"#, #:.W=58*9.8=568.4 \ "N"#

Work is given by the equation: #W=F*d#

We got: #F=568.4 \ "N",d=4 \ "m"#

#:.W=568.4 \ "N"*4 \ "m"=2273.6 \ "J"~~2274 \ "J"#