Question

How much work does it take to raise a `28 kg` weight `49 m`?

Answer 1

`13kJ`

Explanation:

`W=FDeltas`, where:

• `W` = work done (`J`)
• `F` = force in the direction of motion (`N`)
• `Deltas` = distance traveled (`m`)

`W=mgDeltah=28*9.81*49=13kJ`

Answer 2

`13459.32 \ "J"~~13.46 \ "kJ"`

Explanation:

The work done is given by the equation,

`W=F*d`

• `F` is the force applied in newtons

• `d` is the distance moved in meters

The force applied here is the weight of the box, which is,

`28 \ "kg"*9.81 \ "m/s"^2=274.68 \ "N"`

Therefore, the work done is,

`W=274.68 \ "N"*49 \ "m"`

`=13459.32 \ "J"`

`~~13.46 \ "kJ"`