How much work does it take to raise a #28 kg # weight #49 m #?

2 Answers
Apr 25, 2018

Answer:

#13kJ#

Explanation:

#W=FDeltas#, where:

  • #W# = work done (#J#)
  • #F# = force in the direction of motion (#N#)
  • #Deltas# = distance traveled (#m#)

#W=mgDeltah=28*9.81*49=13kJ#

Apr 25, 2018

Answer:

#13459.32 \ "J"~~13.46 \ "kJ"#

Explanation:

The work done is given by the equation,

#W=F*d#

  • #F# is the force applied in newtons

  • #d# is the distance moved in meters

The force applied here is the weight of the box, which is,

#28 \ "kg"*9.81 \ "m/s"^2=274.68 \ "N"#

Therefore, the work done is,

#W=274.68 \ "N"*49 \ "m"#

#=13459.32 \ "J"#

#~~13.46 \ "kJ"#