# How much work is done by the boy pulling his sister 36 m in a wagon as shown in the figure below? Assume no friction acts on the wagon. (Assume d = 36 m and F = 52 N.)

## Mar 20, 2017

The amount of work done is $\text{1600 N"*"m}$at an angle of ${30}^{\text{o}}$, and a horizontal displacement of $\text{36 m}$.

#### Explanation:

Work is done when a force acts on a body, causing that body to move a given number of meters in the same direction as the force. The formula for work is:

W=F*d*costheta", where $W$ is work in Newton-meters, $\left(\text{N"*"m}\right)$, force is Newtons, $\left(\text{N}\right)$, and $\left(\text{d}\right)$ is the displacement in meters over which the force is applied, and $\theta$ is the angle over which the force is applied.

Known:
$\text{F=52 N}$
$\text{d=36 m}$
theta=30^("o"

Unknown: $W$

$W = 52 \text{N"xx36"m"xx"cos30"^("o")=1600"N"*"m}$ (rounded to two significant figures)

The amount of work done is $\text{1600 N"*"m}$at an angle of ${30}^{\text{o}}$, and a horizontal displacement of $\text{36 m}$.