# How much work would it take to horizontally accelerate an object with a mass of 8 kg to 7 m/s on a surface with a kinetic friction coefficient of 2 ?

Apr 29, 2017

Wrong question ..?

#### Explanation:

For the body to be accelerated to 7$m {s}^{- 1}$
we know , work don't in doing so is equal to
W=$F \cdot \mathrm{dS} = \frac{1}{2} M \left({v}_{f}^{2} - {v}_{i}^{2}\right)$

This can be altered due the presence of friction force.
$\left({F}_{a p p l i e d} - {K}_{f} \cdot N\right) \cdot \mathrm{dS} = \frac{1}{2} M \left({v}_{f}^{2} - {v}_{i}^{2}\right)$

To solve this question we have to get at least 1 variables , But here we have got 2 , provided the information is insufficient.