How much work would it take to horizontally accelerate an object with a mass of #8 kg# to #5 m/s# on a surface with a kinetic friction coefficient of #6 #?

1 Answer
Jan 24, 2018

Answer:

#520 N#

**Please note the unit of acceleration will be #m/s^2# not #m/s#

Explanation:

On this horizontal surface amount of frictional force(#f#) acting on the object is #mu×N# = #mu×mg# i.e #6×8×10 N = 480 N#

Now,suppose we have to apply an amount of force #F# to accelerate it at #a=5m/s^2# so,we can write,

#F - f = m×a#

Putting the values we get, #F = (480+40) N# or #520 N#