Question

How much work would it take to horizontally accelerate an object with a mass of `8 kg` to `5 m/s` on a surface with a kinetic friction coefficient of `6`?

Answer 1

`520 N`

**Please note the unit of acceleration will be `m/s^2` not `m/s`

Explanation:

On this horizontal surface amount of frictional force(`f`) acting on the object is `mu×N` = `mu×mg` i.e `6×8×10 N = 480 N`

Now,suppose we have to apply an amount of force `F` to accelerate it at `a=5m/s^2` so,we can write,

`F - f = m×a`

Putting the values we get, `F = (480+40) N` or `520 N`