# How much work would it take to horizontally accelerate an object with a mass of 8 kg to 5 m/s on a surface with a kinetic friction coefficient of 6 ?

Jan 24, 2018

$520 N$

**Please note the unit of acceleration will be $\frac{m}{s} ^ 2$ not $\frac{m}{s}$

#### Explanation:

On this horizontal surface amount of frictional force($f$) acting on the object is mu×N = mu×mg i.e 6×8×10 N = 480 N

Now,suppose we have to apply an amount of force $F$ to accelerate it at $a = 5 \frac{m}{s} ^ 2$ so,we can write,

F - f = m×a

Putting the values we get, $F = \left(480 + 40\right) N$ or $520 N$