# How much work would it take to push a  1 kg  weight up a  2 m  plane that is at an incline of  pi / 6 ?

Dec 4, 2017

#### Answer:

9.8sqrt3

#### Explanation:

work done$=$F.s{F$\rightarrow$Force acting;s$\rightarrow$displacement}

W$=$Fscos$\theta$ where $\theta$ is the angle between force and the resulting displacement.

In this case the displacement is along the direction of force,{$\theta$$=$0}

W$=$Fs

here F$=$mgsin$\theta${gsin$\theta$ is the acceleration of the block kept on an inclined plane.}

Given s$=$2m
mass = 1Kg

substituting and solving:

W= Mg sin$\theta$$\times$s
$\Rightarrow$1Kg$\times$9.8m/s2$\times$2m$\times$sin$\pi$/6$\Rightarrow$9.8$\times$2$\times$sqrt3/2$=$ $9.8$sqrt3

You can also solve by finding the height of the plane{sin$\pi$/6$=$H/s} and using W$=$mgh.{as work is a conservative force}