Question

How much work would it take to push a `1 kg` weight up a `5 m` plane that is at an incline of `pi / 3`?

Answer 1

The work done is found by

`W = mgxxDeltad cos(pi/6) = 42.4J`

Explanation:

In any situation where a force acts and an object moves, the work done by or against that force is given by

`W = FxxDeltad costheta`

where `theta` is the angle between the directions of `vecF` and `vecDeltad`

Since the force we work against here is the force of gravity and the displacement is upward at an angle of `pi/3` relative to the horizontal , the angle between `F_g` and `Deltad` is `pi/6`

Therefore, the work done is

`W = mgxxDeltad cos(pi/6) = (1)(9.8)(5)(sqrt3/2)=42.4J`