How much work would it take to push a  12 kg  weight up a  5 m  plane that is at an incline of  pi / 3 ?

May 18, 2017

The work is $= 509.2 J$

Explanation:

We resolve in a direction parallel to the plane ↗

The work done is

$W = F \cdot d$

The force is the component of the weight

$F = m g \sin \theta$

Therefore,

$W = m g \sin \theta \cdot 5$

$= 12 g \sin \left(\frac{1}{3} \pi\right) \cdot 5$

$= 60 g \sin \left(\frac{1}{3} \pi\right)$

$= 509.2 J$