Question

How much work would it take to push a `2 kg` weight up a `2m` plane that is at an incline of `(5pi) / 12`?

Answer 1

`37.9J`

Explanation:

The formula for work is `W=Fdcostheta`. In this case the incline does not give us the required value for `theta`. We need to use the complement of the incline.

`theta = "completment of incline" = "pi/2 - (5pi)/12 = (6pi)/12 - (5pi)/12 = pi/12`

Here, `F=2*9.81=19.62N, d=2m, costheta=cos(pi/12)=0.9659`

Now multiply: `19.62*2*0.9659`

`W~=37.9J`