# How much work would it take to push a  3 kg  weight up a  7 m  plane that is at an incline of  pi / 6 ?

##### 1 Answer

Work $W = 102.9 \text{ }$Joules

#### Explanation:

The force $F$ required to push a weight a distance $d = 7 \text{ }$meters up parallel to the incline plane at $\theta = \frac{\pi}{6} = {30}^{\circ}$ is

$F = m g \cdot \sin \theta$

considering no frictional force is involve

The work $W$:

$W = F \cdot d = m g \cdot \sin \theta \cdot d = 3 \left(9.8\right) \cdot \sin \left(\frac{\pi}{6}\right) \cdot 7$

$W = 102.9 \text{ }$joules

God bless....I hope the explanation is useful.