# How much work would it take to push a 9 kg  weight up a  11 m  plane that is at an incline of  pi / 12 ?

Work$= 251.1062376 \text{ }$joules

#### Explanation:

The given data:

$\theta = \frac{\pi}{12} = {15}^{\circ}$
mass $m = 9 \text{ }$kg
distance $d = 11 \text{ }$m

Let $F$ be the required force to push the weight
Let $W$ be the work in joules

$F = m \cdot g \cdot \sin \theta$

$F = \left(9\right) \left(9.8\right) \sin {15}^{\circ}$

$F = 22.82783978 \text{ }$N

Compute work $W$

$W = F \cdot d = 22.82783978 \left(11\right)$

$W = 251.1062376 \text{ }$Joules

God bless....I hope the explanation is useful.