How to do this?
1 Answer
Apr 23, 2018
See the answer below...
Explanation:
#" "3-2sin^2theta=sin theta+3#
#=>cancel3-2sin^2theta=sintheta+cancel3#
#=>sintheta+2sin^2theta=0#
#=>sintheta cdot(2sintheta+1)=0# Either,
#sintheta=0" "" "(2sintheta+1)=0#
#=>color(red)(ul(bar(|color(blue)(theta=npi))|)" "=>sintheta=-1/2#
#" "=>color(red)(ul(bar(|color(blue)(theta=npi-(-1)^n cdot pi/6))|# Note:-
#n in I# Hope it helps...
Thank you...
:-)
