# How to express e^(2-i)  in the form a + ib?

${e}^{2} \cdot {e}^{- 1 i}$
$r {e}^{- i \theta} = r \left[\cos \left(\theta\right) - i \sin \left(\theta\right)\right]$ with $\theta = 1$ in radians;
${e}^{2} \left[\cos \left(1\right) - i \sin \left(1\right)\right] \cong 4 - 6 i$