# How to find a horizontal asymptote (x+3)/(x^2-9)?

Jan 25, 2016

y = 0 ( x-axis )

#### Explanation:

When the degree of the numerator < degree of denominator a

horizontal denominator can be found.

The numerator is of degree 1 and the denominator of degree 2

In this case the horizontal asymptote is y = 0
graph{(x+3)/(x^2 - 9) [-10, 10, -5, 5]}