Question

How to find a horizontal asymptote `(x+3)/(x^2-9)`?

Answer 1

y = 0 ( x-axis )

Explanation:

When the degree of the numerator < degree of denominator a

horizontal denominator can be found.

The numerator is of degree 1 and the denominator of degree 2

In this case the horizontal asymptote is y = 0
graph{(x+3)/(x^2 - 9) [-10, 10, -5, 5]}