How to find for the missing parts in the following diagrams below?

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1 Answer
Jim G.
Nov 22, 2017

#"see explanation"#

Explanation:

#color(blue)"First diagram"#

#"we can solve using "color(blue)"trig. ratios"#

#tan60^@="opposite"/"adjacent"="long"/(5sqrt3)#

#rArr"long "=5sqrt3xxtan60^@=5sqrt3xxsqrt3=15#

#cos60^@="adjacent"/"hypotenuse"=(5sqrt3)/"hypotenuse"#

#rArr"hypotenuse "=(5sqrt3)/(cos60^@)=(5sqrt3)/(1/2)=10sqrt3#

#color(blue)"Second diagram"#

#sin30^@="opposite"/"hypotenuse"="short"/(6sqrt3)#

#rArr"short "=6sqrt3xxsin30^@=6sqrt3xx1/2=3sqrt3#

#cos30^@="long"/(6sqrt3)#

#rArr"long "=6sqrt3xxcos30^@=6sqrt3xxsqrt3/2=9#

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