How to find instantaneous rate of change for #s(t) = t^3 + t# when t=2?
1 Answer
Apr 20, 2016
13
Explanation:
This is just the value of the derivative when t = 2
#rArr s'(t) = 3t^2 + 1#
#rArr s'(2) = 3(2)^2 + 1 = 13 #
