How to find instantaneous rate of change for #sqrt(4t + 6)# when t=6?
1 Answer
Jul 24, 2017
Explanation:
#"the instantaneous value is the derivative of f(t) at x = a"#
#"differentiate using the "color(blue)"chain rule"#
#"given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larr" chain rule"#
#f(t)=sqrt(4t+6)=(4t+6)^(1/2)#
#rArrf'(t)=1/2(4t+6)^(-1/2)xxd/dt(4t+6)#
#color(white)(rArrf'(t))=2/(4t+6)^(1/2)#
#rArrf'(6)=2/sqrt30#
