How to find the asymptotes of Q(x) = (2x^2) / (x^2 - 5x - 6)?

Jan 3, 2016

First, factor the denominator ...

${x}^{2} - 5 x - 6 = \left(x - 6\right) \left(x + 1\right)$

Explanation:

Vertical asymptotes when the denominator is equal to zero ...

$x = 6 \mathmr{and} x = - 1$

Horizontal asymptote : $y = \frac{2 {x}^{2}}{x} ^ 2 = 2$

hope that helped