How to find the vector unit normal?

Question

$bbr(t)=sqrt(2)tbbi+e^tbbj-e^-tbbk$
$t=0$

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Answer 1 · 2018-03-31T23:48:29

$bbr(0)=bbj-bbk$

We have $bbr(t)=sqrt2tbbi+e^tbbj-e^(-t)bbk$ . To find $bbr(0)$ , we simply plug $0$ into the equation.

$bbr(0)=sqrt2(0)bbi+e^0bbj-e^-0bbk=bbj-bbk$