# How to find the x and y-intercept given 3y=-6x+3?

Apr 8, 2018

x-intercept $= \frac{1}{2}$

y-intercept $= 1$

#### Explanation:

$3 y = - 6 x + 3$

To find the x-intercept, set y equal to zero:

$3 \left(0\right) = - 6 x + 3$

$0 = - 6 x + 3$ (Subtract 3 from both sides)

$- 3 = - 6 x$ (Divide both sides by -6)

$\frac{1}{2} = x$

To find the y-intercept, set x equal to zero:

$3 y = - 6 \left(0\right) + 3$

$3 y = 0 + 3$

$3 y = 3$ (Divide both sides by 3)

$y = 1$

Apr 8, 2018

$\text{x-intercept "=1/2," y-intercept } = 1$

#### Explanation:

$\text{to find the intercepts, that is where the graph crosses }$
$\text{the x and y axes}$

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

$3 y = - 6 x + 3 \Rightarrow y = - 2 x + 1$

$x = 0 \Rightarrow y = 0 + 1 = 1 \leftarrow \textcolor{red}{\text{y-intercept}}$

$y = 0 \Rightarrow - 2 x + 1 = 0 \Rightarrow x = \frac{1}{2} \leftarrow \textcolor{red}{\text{x-intercept}}$
graph{(y+2x-1)((x-1/2)^2+(y-0)^2-0.04)((x-0)^2+(y-1)^2-0.04)=0 [-10, 10, -5, 5]}