Question

How to find the x and y-intercept given `3y=-6x+3`?

Answer 1

x-intercept `=1/2`

y-intercept `=1`

Explanation:

`3y=-6x+3`

To find the x-intercept, set y equal to zero:

`3(0)=-6x+3`

`0=-6x+3` (Subtract 3 from both sides)

`-3=-6x` (Divide both sides by -6)

`1/2=x`

To find the y-intercept, set x equal to zero:

`3y=-6(0)+3`

`3y=0+3`

`3y=3` (Divide both sides by 3)

`y=1`

Answer 2

`"x-intercept "=1/2," y-intercept "=1`

Explanation:

`"to find the intercepts, that is where the graph crosses "`
`"the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`3y=-6x+3rArry=-2x+1`

`x=0rArry=0+1=1larrcolor(red)"y-intercept"`

`y=0rArr-2x+1=0rArrx=1/2larrcolor(red)"x-intercept"`
graph{(y+2x-1)((x-1/2)^2+(y-0)^2-0.04)((x-0)^2+(y-1)^2-0.04)=0 [-10, 10, -5, 5]}