# How to find the x and y-intercept given f(x)= 9x^2-2x-4?

May 12, 2015

To find y-inercept, make x = 0 -> y = -4

To find x-intercepts, make y = 0:

Solve quadratic equation: $9 {x}^{2} - 2 x - 4 = 0$

$D = {d}^{2} = 4 + 144 = 148 \to d = \pm 2 s q r 37$

Two x-intercepts: $x = \frac{4}{18} + \frac{2 s q r 37}{18.}$

$\mathmr{and} x = \frac{4}{18} - \frac{2 s q r 37}{18}$