How to find the y-intercept given #f(x) = -3x^2 + 6x -2#?
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"Question #c42fa"
1 Answer
Mar 14, 2018
Explanation:
#"The graph crosses the y-axis when x = 0"#
#"substituting x = 0 into the equation gives the y-intercept"#
#rArrf(0)=0+0-2=-2larrcolor(red)"y-intercept"#
graph{(y+3x^2-6x+2)((x-0)^2+(y+2)^2-0.04)=0 [-10, 10, -5, 5]}