# How to find the y-intercept given y = x^2 + 2x - 3?

The $y$ intercept is a point on the $y$-axis. Where the $x$-coefficients are all $0$.
Put in $0$ for $x$ and find $y$.
$y = {\left(0\right)}^{2} + 2 \left(0\right) - 3 = 3$
The $y$-intercept is $- 3$ (or $\left(0 , - 3\right)$ depending on your grader's preference).