How to prove the following? #cot^(-1)7+cot^(-1)8+cot^(-1)18=cot^(-1)3#

Question

22934 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-01T15:11:39

#LHS=cot^-1 7+cot^-1 8+cot^-1 18#

#=cot^-1 ((7xx8-1)/(8+7))+cot^-1 18#

#=cot^-1 (55/15)+cot^-1 18#

#=cot^-1 (11/3)+cot^-1 18#

#=cot^-1 ((11/3xx18-1)/(11/3+18))#

#=cot^-1 ((66-1)/((11+18*3)/3))#

#=cot^-1 3=RHS#