How to prove these ?

If #a,b ϵ R# then prove that if #a+b=0# then #b=-a# ?

1 Answer
Sep 8, 2017

Add #-a# to both members of the equality:

#-a+ (a+b) = -a#

using the commutative property of the sum of two real numbers:

#-a + (a+b) = (-a+a) + b#

by the definition of opposite of a real number:

# (-a+a) + b= 0 + b #

and as zero is the identity element of the sum:

#0+b = b#

Then by the transitive property of the equality of two real numbers:

#b = -a#