Question

How to solve log(6)x = log(3)2x ?

Answer 1

`x=1/6`

Explanation:

`log_6x=log_3 2x` can be written as

`logx/log6=(log2x)/log3`

or `logx/log6=(log2+logx)/log3`

or `log3logx=log6log2+log6logx`

or `logx(log6-log3)=-log6log2`

or `logxlog2=-log6log2`

or `logx=-log6=log(1/6)`

Hence `x=1/6`