How to transform an expression to radical form #(125)^(-1/3)#?

1 Answer
Jul 25, 2015

You use the fact that #x^(1/n)# is equivalent to #root(n)(x)#.

Explanation:

In order to convert your expression to radical form, you need to use two proprties of fractional exponents. The first one tells you that

#x^(-y) = 1/x^y#

In your case, the exponent is equal to #-1/3#, which means that the expression is equivalent to

#(125)^(-1/3) = 1/(125)^(1/3)#

Next, use the fact that raising a number to a fractional exponent that has the form #1/n# is equivalent to extracting the #n^"th"# root of that number.

In your case, the fractional exponent is #1/3#, which means that you have

#1/(125)^(1/3) = 1/root(3)(125)#

As it turns out, #125# is a perfect cube, which means that you can write it as

#125 = 25 * 5 = 5 * 5 * 5 = 5^3#

The expression becomes

#1/root(3)(125) = 1/root(3)(5^3) = color(green)(1/5)#