# How to use the discriminant to find out how many real number roots an equation has for x^2 - 8x + 3 = 0?

Two real roots

#### Explanation:

Comparing given quadratic equation: ${x}^{2} - 8 x + 3 = 0$ with the standard form of quadratic equation: $a {x}^{2} + b x + c = 0$ we get

$a = 1 , b = - 8 , c = 3$

The value of discriminant

${b}^{2} - 4 a c = {\left(- 8\right)}^{2} - 4 \left(1\right) \left(3\right) = 64 - 12 = 52 > 0$

Since, the discriminant ${b}^{2} - 4 a c > 0$ hence both the roots are real & distinct