Question

How to use the discriminant to find out how many real number roots an equation has for `x^2 - 8x + 3 = 0`?

Answer 1

Two real roots

Explanation:

Comparing given quadratic equation: `x^2-8x+3=0` with the standard form of quadratic equation: `ax^2+bx+c=0` we get

`a=1, b=-8, c=3`

The value of discriminant

`b^2-4ac=(-8)^2-4(1)(3)=64-12=52>0`

Since, the discriminant `b^2-4ac>0` hence both the roots are real & distinct