How to use the discriminant to find out how many real number roots an equation has for #x^2 - 4x + 3 = 0#? Algebra Quadratic Equations and Functions Solutions Using the Discriminant 1 Answer sankarankalyanam Apr 16, 2018 #color(purple)("TWO REAL ROOTS"# Explanation: #x^2 - 4x + 3 # #"Discriminant " D = b^2 - 4ac# In this case, #color(brown)(D = b^2 - 4ac) = 16 - (4 * 1 * 3) = 4, " which is "color(blue)( > 0) " and hence has two real roots ", color(green)(+-2# Answer link Related questions How do you find the number of solutions using the discriminant? What is the Discriminant? How does the discriminant affect the graph? Why is the discriminant useful? How do you determine the number of real solutions to #-3x^2+4x+1=0#? Can you find a discriminant for a linear equation? What is the discriminant of #2x^2-4x+5=0#? What type of solutions and how many solutions does the equation #41x^2-31x-52=0# have? How do you determine if a solution to a quadratic equation is rational or irrational by using... Is the solution to #x^2=5x# rational or irrational? See all questions in Solutions Using the Discriminant Impact of this question 5967 views around the world You can reuse this answer Creative Commons License