# How to use the discriminant to find out what type of solutions the equation has for 4x^2+4x+1?

##### 1 Answer
May 18, 2015

D = b^2 - 4ac = 16 - 16 = 0.

There is double root at $x = \left(- \frac{b}{2} a\right) = - \frac{4}{8} = - \frac{1}{2}$