How to write an equation in standard form for a line through (4,3); slope 1/2?

1 Answer
May 30, 2018

#x-2y=-2#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"obtain the equation in "color(blue)"slope-intercept form"#

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"here "m=1/2#

#y=1/2x+blarrcolor(blue)"is the partial equation"#

#"to find b substitute "(4,3)" into the partial equation"#

#3=2+brArrb=3-2=1#

#y=1/2x+1larrcolor(red)"in slope-intercept form"#

#"multiply through by 2"#

#2y=x+2#

#x-2y=-2larrcolor(red)"in standard form"#