# How would one work out the oxidation number or Chlorine in NH_4ClO_4?

Jul 25, 2016

The oxidation number of chlorine in perchlorate is $V I I +$.

#### Explanation:

Chlorine achieves its maximum oxidation number in perchlorate, i.e. $C l \left(V I I +\right)$.

How did I find the oxidation number? Well, the oxidation number of oxygen in oxides is typically $- I I$, and it is here. The sum of the oxidation numbers is the charge on the ion, here $- 1$. And thus, $- 1 = 4 \times \left(- 2\right) + C {l}_{\text{ON}}$. Capisce?

What is the oxidation state of $C l$ in $C l {O}_{3}^{-} \text{ , chlorate ion?}$.

As a matter of interest, ammonium perchlorate is a prohibited substance. It is a potent oxidant, and would cause police officers to have kittens.