# How would you balance: KO2(s) + H2O(l) --? KOH(aq) + O2(g) +H2O2(aq)?

##### 1 Answer

#### Answer:

Provided that the given reactants and products are correct, the balanced equation is

#### Explanation:

First tally all the atoms involved in the reaction. You can do this by looking at the subscripts.

*left side:*

K = 1

O = 2 + 1 (do not add this up yet)

H = 2

*right side:*

K = 1

O = 1 + 2 + 2 (do not add this up yet)

H = 1 + 2 (do not add this up yet)

Always remember that in balancing equations, you are not allowed to change the subscript, but you are allowed to put coefficients before the chemical formulas.

Let's start to balance the easiest atom, in this case the

Since

*left side:*

K = 1

O = 2 + 1

H = 2

*right side:*

K = (1 x

O = (1 x

H = (1 x

Notice that since the

*left side:*

K = 1

O = 2 + (1 x

H = 2 x **4**

*right side:*

K = 1 x 2 = **2**

O = (1 x 2) + 2 + 2

H = (1 x 2) + 2 = **4**

Also, you have two

*left side:*

K = 1 x **2**

O = (2 x

H = 2 x 2 = **4**

*right side:*

K = 1 x 2 = **2**

O = (1 x 2) + 2 + 2

H = (1 x 2) + 2 = **4**

Now the only thing left to balance are the

*left side:*

K = 1 x 2 = **2**

O = (2 x 2) + (1 x 2) = **6**

H = 2 x 2 = **4**

*right side:*

K = 1 x 2 = **2**

O = (1 x 2) + 2 + 2 = **6**

H = (1 x 2) + 2 = **4**

The equation is already balanced.