# How would you balance: Na2SO3+S8 --> Na2S2O3?

##### 2 Answers

#### Explanation:

It's Actually easy.

First Let's Check The Equation.

In L.H.S, We can see two sulphur atoms, but in R.H.S, we can see only one.

According to this equation, it's a redox reaction. Because value of S in

The sulphur is being oxidized (

The key changes are:

According to these equations, second one must be multiplied by 8 for balance.

Put them all together and check the

Total Balance:

What we gots is a

#### Explanation:

Where sulfur, as

And so reduction....

And oxidation...

We add the equations together to eliminate the electrons...

And we cancel common reagents...

The which, I think, is balanced with respect to mass and charge...as indeed it must be if we reflect chemical reality...