How would you balance: Na2SO3+S8 --> Na2S2O3?
It's Actually easy.
First Let's Check The Equation.
In L.H.S, We can see two sulphur atoms, but in R.H.S, we can see only one.
According to this equation, it's a redox reaction. Because value of S in
The sulphur is being oxidized (
The key changes are:
According to these equations, second one must be multiplied by 8 for balance.
Put them all together and check the
What we gots is a
Where sulfur, as
And so reduction....
We add the equations together to eliminate the electrons...
And we cancel common reagents...
The which, I think, is balanced with respect to mass and charge...as indeed it must be if we reflect chemical reality...