# How would you balance: (NH_4)_2SO_4 + KOH -> K_2SO_4 + NH_3 + H_2O?

Jan 2, 2016

You balance it stoichiometrically. What do I mean?

#### Explanation:

In every chemical reaction, both MASS and CHARGE are conserved. This is stoichiometry: for every product particle, there is a corresponding reactant particle.

So:

${\left(N {H}_{4}\right)}_{2} S {O}_{4} \left(a q\right) + 2 K O H \left(a q\right) \rightarrow {K}_{2} S {O}_{4} \left(a q\right) + 2 N {H}_{3} \left(a q\right) + 2 {H}_{2} O \left(l\right)$

Does this reaction satisfy the condition of stoichiometry? Charge is balanced certainly, but what about mass? There are 10 $H$ particles as reactants. Are there 10 $H$ products? If not, the reaction is not stoichiometric.

Stoichiometry is not only practised by chemists. It is practised by shop-keepers, bankers, and salesman. For every credit there must be a corresponding debit. If there is not then someone, (YOU!), has made a mistake.