# How would you balance the following chemical equation: KClO_3 -> KCl + O_2?

Jul 20, 2016

$2 K C l {O}_{3} \to 2 K C l + 3 {O}_{2}$

#### Explanation:

Given unbalanced equation:

$K C l {O}_{3} \to K C l + {O}_{2}$

Since the number of oxygens on the right hand side is even, we need a multiplier on the left hand side which is a multiple of $2$.

We find that $2$ is sufficient, resulting in a total of $6$ oxygens on the left hand side, requiring a multiplier $3$ for the ${O}_{2}$ on the right hand side, etc.

$2 K C l {O}_{3} \to 2 K C l + 3 {O}_{2}$