# How would you balance the following equation: aluminum + oxygen gas --> aluminum oxide?

Dec 18, 2015

$4 \text{Al}$ $+$ $3 {\text{O"_2rarr2"Al"_2"O}}_{3}$

#### Explanation:

$\text{Al}$ $+$ ${\text{O"_2rarr"Al"_2"O}}_{3}$

This is the unbalanced equation described.

Achieve a common $6$ oxygen atoms on either side of the equation.

$\text{Al}$ $+$ $3 {\text{O"_2rarr2"Al"_2"O}}_{3}$

Now, since there are $1$ and $4$ aluminum atoms on each side respectively, change the coefficient on the reactants side to $4$.

Balanced form:

$4 \text{Al}$ $+$ $3 {\text{O"_2rarr2"Al"_2"O}}_{3}$