# How would you balance the following equation: HI(g) → H2(g) + I2(g)?

$2 H I \left(g\right) \to H 2 \left(g\right) + I 2 \left(g\right)$
There are 2 Hydrogen atoms and 2 Iodine atoms on the right so the have to be 2 of each on the left as well, so there are $2$ $H I$ molecules on the left.