# How would you balance the following equation: S8 + O2 --> SO3?

Jan 4, 2016

The balanced equation is $\text{S"_8+"12O"_2}$$\rightarrow$$\text{8SO"_3}$.

#### Explanation:

Unbalanced Equation
$\text{S"_8+"O"_2}$$\rightarrow$$\text{SO"_3}$

Balance the S. There are $8$ atoms (or moles) of S on the left side and 1 on the right side. Place a coefficient of $8$ in front of $\text{SO"_3}$.

$\text{S"_8+"O"_2}$$\rightarrow$$\text{8SO"_3}$

Now there are $8$ atoms (or moles) of sulfur on both sides of the equation.

Balance the O. There are $2$ atoms (or moles) of O on the left side and $24$ on the right. Place a coefficient of $12$ in front of $\text{O"_2}$.

$\text{S"_8+"12O"_2}$$\rightarrow$$\text{8SO"_3}$

There are now equal numbers of atoms (or moles) of sulfur and oxygen on both sides and the equation is balanced.