# How would you balance the following equation: S8 + O2 --> SO3?

${S}_{8} + \textcolor{red}{12} {O}_{2} \to \textcolor{b l u e}{8} S {O}_{3}$
To start balancing this reaction, we can first multiply $S$ by $8$ which will make the number of oxygen atoms in the product $24$, then we multiply $O$ by $12$.
${S}_{8} + \textcolor{red}{12} {O}_{2} \to \textcolor{b l u e}{8} S {O}_{3}$