How would you balance this equation: #?Pb(NO_3)_2 → ?Pb + ?NO_2 + ?O_2#?

1 Answer
Mar 14, 2017

Answer:

#Pb(NO_3)_2 rarr Pb + O2 + 2NO_2#

Explanation:

To balance this reaction first we have to see the number of moles of each element.

#Pb(NO_3)_2 rarr Pb + O_2 + NO_2#

(Pb = 1) (Pb = 1)

#(N = 2)# #(O = cancel(4)^6)#

(O = 6 ) #(N = cancel(1)^2)#

First try adding 3 as the coefficient in front of #O_2# and 2 in front of #NO_2# but that will be wrong as 2NO2 has 4 oxygen atoms which we dont have, so to make a balanced equation we must remove 3 from O2 and add 2 in front of #NO_2#

= #Pb(NO_3)_2 rarr Pb + O2 + 2NO_2#