How would you calculate the specific beat of silver, given that 280 g of the metal absorbed 136 calories when changed from 22.13°C to 30.79°C?

1 Answer
Dec 1, 2016

Answer:

#c_"Ag"=0.056"cal"/("g"*^@"C")#

Explanation:

The equation you'll need is the following:
http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html
where #Q# is in calories, #c# is in #"cal"/("g"*^@"C")#, #m# is mass in grams, and #DeltaT# is the change in Celcius temperature. #DeltaT=T_"final"-T_"initial"#

#Q="136 cal"#
#m="280 g"#
#T_"initial"="22.13"^@"C"#
#T_"final"="30.79"^@"C"#
#DeltaT="30.79"^@"C"-"22.13"^@"C"#"="8.66"^@"C"#

Rearrange the equation to isolate #c#.

#c_"Ag"=Q/(mDeltaT)#

#c_"Ag"=(136"cal")/(280"g"*8.66^@"C")#

#c_"Ag"=0.056"cal"/("g"*^@"C")#