Question

How would you calculate the speed at which the moon revolves around the earth in m/s?

Answer 1

speed equals orbital radius times the orbital angular speed

Explanation:

The moon is 384,000 km away from the Earth. It revolves around the earth in 27.3 days.

it's speed is : `v = r omega = r (2pi)/T=\frac{2\pi.r}{T}`,

where `T` is the lunar orbital period, and `r` the orbital radius of moon (the moon follows an ellipse but the eccentricity is small enough that you can treat it as a circle.)

This gives you,

`v = (384,000 \quad km)\times (2pi)/((27.3\quad days)\times (86400\quad s/(day)))`
`= 1.023 \quad(km)/s`