How would you calculate the speed at which the moon revolves around the earth in m/s?

Mar 8, 2016

speed equals orbital radius times the orbital angular speed

Explanation:

The moon is 384,000 km away from the Earth. It revolves around the earth in 27.3 days.

it's speed is : $v = r \omega = r \frac{2 \pi}{T} = \setminus \frac{2 \setminus \pi . r}{T}$,

where $T$ is the lunar orbital period, and $r$ the orbital radius of moon (the moon follows an ellipse but the eccentricity is small enough that you can treat it as a circle.)

This gives you,

$v = \left(384 , 000 \setminus \quad k m\right) \setminus \times \frac{2 \pi}{\left(27.3 \setminus \quad \mathrm{da} y s\right) \setminus \times \left(86400 \setminus \quad \frac{s}{\mathrm{da} y}\right)}$
$= 1.023 \setminus \quad \frac{k m}{s}$