How would you determine the Lewis structure for #CO#?

1 Answer
Nov 15, 2016

Answer:

There are 10 valence electrons to distribute........

Explanation:

There are 10 valence electrons to distribute........6 from oxygen, and 4 from carbon.

Lewis structures of #""^(+):O-=C:^(-)# OR #:ddotO=C:# are appropriate. I tend to favour the one with formal charge separation inasmuch as carbon monoxide generally binds thru the carbon rather than the oxygen.