How would you determine the oxidation number of Sulpher in #SO_3^-2#?

1 Answer
Jun 23, 2016

Answer:

The oxidation state of sulfur in #SO_3^(2-)# is #+IV#.

Explanation:

The sum of the oxidation numbers/states of the individual elements in the species must equal the charge on the ion. #O# normally takes a #-II# oxidation state and it does here.

Thus #-2=3xx(-2)+ON_"sulfur"#

And so #ON_"sulfur"=-2+6=+4,# i.e. #+IV#.