How would you find the equation of the circle, center at (2/3) with a radius of 10 units?
I am assuming that the centre = ( 2 , 3)
The standard form of the equation of a circle is:
#(x - a )^2 + (y - b )^2 = r^2#
where (a , b) are the coords of centre and r , the radius
here (a , b ) = (2, 3 ) and r = 10. Substitute values into equation.
# rArr (x - 2)^2 + (y - 3)^2 = 100 #