Question

How would you find the exact value of the six trigonometric function of -3pi/2?

Answer 1

`sin ((-3pi)/2)=1`,`" " "cos ((-3pi)/2)=0`,`" " "tan ((-3pi)/2)=oo`

`csc ((-3pi)/2)=1`,`" " "sec ((-3pi)/2)=oo`,`" " "cot ((-3pi)/2)=0`

Explanation:

`sin ((-3pi)/2)=sin ((pi)/2)=1`,
`cos ((-3pi)/2)=cos ((pi)/2)=0`,
`tan ((-3pi)/2)=tan ((pi)/2)=oo`

`csc ((-3pi)/2)=csc ((pi)/2)=1`,
`sec ((-3pi)/2)=sec ((pi)/2)=oo`,
`cot ((-3pi)/2)=cot ((pi)/2)=0`

God bless....I hope the explanation is useful.