Question

How would you find the exact value of the six trigonometric function of -7pi/4?

Answer 1

#{: (sin(-(7pi)/4)=sqrt(2)/2,color(white)("XX"),csc(-(7pi)/4)=sqrt(2)), (cos(-(7pi)/4)=sqrt(2)/2,,sec(-(7pi)/4)=sqrt(2)), (tan(-(7pi)/4)=1,,cot(-(7pi)/4)=1) :}#

Explanation:

Note that an angle of `-(7pi)/4` is equivalent to an angle of `pi/4` which is one of the standard/common angles.