How would you simplify this? I have to show all my work.

Question

#(8y^(3)-16y^(2))/(2y^(3)-2y^(2)-4y)#

889 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-11-02T20:52:06

#=(4y)/((y+1))#

Find factors first: look for common factors

#(8y^3-16y^2)/(2y^3-2y^2-4y) #

#= (8y^2(y-2))/(2y(y^2-y-2))" "larr# quadratic trinomial

#=(8y^2(y-2))/(2y(y-2)(y+1))" "larr# cancel like factors

#=(cancel8^4y^2(cancel(y-2)))/(cancel2y(cancel(y-2))(y+1))#

#=(4y)/((y+1))#